Riemann sum (little boxes and adding them up)
Graphical interpretation of integrals
Given a constant acceleration, the velocity increases linearly (area under accel graph)
Given linear velocity, the position increases quadratically (area under velocity graph)
Computing the Definite integral: Get area under graph
Indefinite integral: Gets us the state function as we move up and down kinematic ladder
C is Not Needed for Definite IntegralsIndefinite Integral: Finds a general function. You must solve for C using an initial condition.
Definite Integral: Finds the change from a known starting value. It's more direct and avoids C.
The Fundamental Theorem of Calculus states that, in a sense, the derivative and integral are inverses of each other. It's extremely valuable to know that derivatives ("instantaneous rate of change") and integration ("area under a curve") are linked, and furthermore can be interpreted as opposites. This fundamental relationship is why it's called the "fundamental" theorem—it bridges the two main operations of calculus and shows they are intimately connected.
Remember that a definite integral computes the area under a curve between two points. In the image above, we're finding the area under the curve from to .
Athlete runs at 15 km/h. Athlete is 7.5 km away from finish line. Bird flies at instantaneous velocity of 30 km/h. Bird starts from athelete, flies toward finish line, and turns back toward athelete. Repeats until athelete crosses finish line.
How many km does the bird fly?
If we tried drawing kinematic graphs, it would be tricky because toward the end, the bird would be oscillating very quickly between the athlete and finish line.
Zeno’s Dichotomy paradox (sometimes mixed with the Achilles and the Tortoise paradox) says that to reach a finish line, you must first get halfway there, then half of the remaining distance, then half of that, and so on. Since there are infinitely many halfway points, Zeno argued that motion should be impossible.
Answer: 7.5 km in 15 km/h = 0.5 h. Bird flies at 30 km/h for 0.5 h = 15 km.
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